Question

интеграл x/√(x^4+1) dx

Answer 1

$\displaystyle\int\frac{xdx}{\sqrt{x^4+1}}=\frac{1}{2}\int\frac{d(x^2)}{\sqrt{x^4+1}}=\frac{1}{2}ln|x^2+\sqrt{x^4+1}|+C$