Question

помогите найти значение выражения ​

Answer 1

$(x^{2}-100)*\frac{x^{2}+6x+9}{(x-10)(x+3)} =(x+10)(x-10)*\frac{(x+3)(x+3)}{(x-10)(x+3)}=\frac{(x+10)(x-10)(x+3)(x+3)}{(x-10)(x+3)} =\\\\=(x+10)(x+3)$

$(7+10)(7+3)=17*10=170$

Answer 2

Ответ:

Объяснение:

$(x^{2} -100)*\frac{(x+3)^{2} }{(x-10)(x+3)}$=$(x-10)(x+10)*\frac{(x+3)(x+3) }{(x-10)(x+3)}$=$\frac{(x-10)(x+10)(x+3)}{(x-10)} =(x+10)(x+3)=17*10=170$