Question

помогите пожалуйста​

Answer 1

1. $\frac{4}{11} * 1\frac{21}{100} = \frac{4}{11} * \frac{121}{100} = \frac{11}{25}$

2. $4\frac{4}{7}-\frac{3}{7} * (\frac{5}{14}+\frac{17}{21}) = \frac{32}{7} - \frac{3}{7} * (\frac{5}{2*7} +\frac{17}{3*7})= \frac{32}{7}-\frac{3}{7} *\frac{3*5+17*2}{2*3*7} =$

$= \frac{32}{7} -\frac{3}{7} *\frac{49}{42} = \frac{32}{7}-\frac{1}{2} =\frac{32*2-1*7}{14} = \frac{57}{14} = 4\frac{1}{14}$

3. $4\frac{5}{7}-2\frac{2}{5} * 1\frac{19}{36} - (\frac{5}{12}+\frac{13}{20} ) *\frac{9}{16} = \frac{47}{105}$

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1) $\frac{5}{12} +\frac{13}{20} = \frac{5}{4*3} +\frac{13}{4*5} = \frac{5*5+13*3}{4*3*5} =\frac{25+39}{60} = \frac{64}{60} = 1 \frac{4}{60} = 1 \frac{1}{15}$

2) $2 \frac{2}{5} * 1\frac{19}{36} = \frac{12}{5} * \frac{55}{36} = \frac{11}{3} = 3 \frac{2}{3}$

3) $1 \frac{1}{15} * \frac{9}{16} = \frac{16}{15} * \frac{9}{16} = \frac{3}{5}$

4)$4 \frac{5}{7} - 3\frac{2}{3} = \frac{33}{7} - \frac{11}{3} = \frac{33*3-11*7}{3*7} = \frac{99-77}{21} = \frac{22}{21} = 1\frac{1}{21}$

5) $1\frac{1}{21} - \frac{3}{5} = \frac{22}{21} - \frac{3}{5} = \frac{22*5-3*21}{21*5} = \frac{110-63}{105} = \frac{47}{105}$