Question

Элементы высшей математики. Интегралы.

Answer 1

$\displaystyle\int\frac{cos(6x)}{sin^7(6x)}dx=\frac{1}{6}\int\frac{cos(6x)}{sin^7(6x)}d(6x)=\frac{1}{6}\int\frac{d(sin(6x))}{sin^7(6x)}=\\=-\frac{1}{36sin^6(6x)}+C$