Question

Решите квадратное уравнение неполным способом с решением
4x^2-1=0
6x^2-9=0

Answer 1

$4x^{2} - 1 = 0 \\ 4x^{2} = 1 \\\\ x^{2} = \dfrac{1}{4} \\\\ x_{1} = -\dfrac{1}{2} \\\\ x_{2} = \dfrac{1}{2}$

Ответ: $x_{1} = -\dfrac{1}{2} ;\;\;\;\;\; x_{2} = \dfrac{1}{2}$

$6x^{2} - 9 = 0 \\ 6x^{2} = 9 \\\\ x^{2} = \dfrac{9}{6} \\\\ x_{1} = -\dfrac{\sqrt{6}}{2} \\\\ x_{2} = \dfrac{\sqrt{6}}{2}$

Ответ: $x_{1} = -\dfrac{\sqrt{6}}{2} ;\;\;\;\;\; x_{2} = \dfrac{\sqrt{6}}{2}$

Answer 2

Ответ:

1) x = ± ½;

2) x = ± √6/2.

Пошаговое объяснение:

1)

$4 {x}^{2} - 1 = 0 \\ 4 {x}^{2} = 1 \\ {x}^{2} = \frac{1}{4} \\ x = + - \frac{1}{2}$

2)

$6 {x}^{2} - 9 = 0 \\ 6 {x}^{2} = 9 \\ {x}^{2} = \frac{9}{6} \\ {x}^{2} = \frac{3}{2} \\ x = + - \frac{ \sqrt{3} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = + - \frac{ \sqrt{6} }{2}$