Question

(х+4)(2х-3)-(5х-6)(х-3)=10 дискриминант

Answer 1

$2 {x}^{2} - 3x + 8x - 12 -5 {x}^{2} - 15x - 6x + 18 = 10 \\ 7 {x}^{2} - 16x + 4 = 0 \\ d = 256 - 4 \times 7 \times 4 = 256 - 112 = 144 = {12}^{2} \\ x1 = \frac{16 + 12}{14} = \frac{28}{14} = 2 \\ x2 = \frac{16 - 12}{14} = \frac{4}{14} = \frac{2}{7}$

Answer 2

Ответ:

2x^2-3x+8x-12-(5x^2-15x-6x+18)-10=0

2x^2-3x+8x-12-5x^2+15x+6x-18-10=0

-3x^2+26x-40=0. -1

3x^2-26x+40=0

D=676-480=196

✓D=14

x1=40/6=6 4/6

x2=-12/6= -0.5

В-дь:6 4/6; -0.5