Question

Номер 1,2,3 Даю 33 б.

Answer 1

1)

$1) 4x^2-81y^2=(2x-9y)(2x+9y)\\2) a^2b^2-\frac{16}{9} =(ab-\frac{4}{3} )(ab+\frac{4}{3} )\\3) 1,69y^{14}-900z^8=(1,3y^7-30z^4)(1,3y^7+30z^4)\\4) -1+36a^6b^{10}=(6a^3b^5-1)(6a^3b^5+1)\\5) 1\frac{24}{25} m^6n^4-1\frac{9}{16} a^2b^8=(\frac{7}{5} m^3n^2-\frac{5}{4} ab^4)(\frac{7}{5} m^3n^2+\frac{5}{4} ab^4)\\6) 3^{4k}-25= ( 3 k - 2 ) * ( 3 k + 2 )$

2)

$1) (x-3)^2-25=(x-3-25)(x+3-25)=(x-28)(x-22)\\2) a^6-(a+4)^2=(a^3-a-4)(a^3+a+4)$

3)

$(3x+4)^2-(2x-3)^2=0\\(3x+4-2x+3)(3x+4+2x-3)=0\\(x+7)(5x+1)=0\\x_1=-7\\x_2=-\frac{1}{5}$