Question

раскройте скобки, даю 20 баллов!!!​

Answer 1

$(\frac{1}{3}x^{2} -\frac{1}{4}y^3)(\frac{1}{3}x^{2} + \frac{1}{4}y^3)=\frac{1}{9}x^4-\frac{1}{16}y^6$

Answer 2

Ответ:

$\frac{1}{9} \times x {}^{4} - \frac{1}{12} \times x {}^{2} \times y {}^{3} + \frac{1}{12} \times x {}^{2} \times y {}^{3} - \frac{1}{16} \times y {}^{9}$