Question

Решить уравнение, пожалуйста на ЛИСТОЧКЕ и сфоткать подробно

Answer 1

ОДЗ: $\displaystyle \tt x\ne0,5$

$\displaystyle \tt \frac{4z^3-z}{1-2z}=0\\\\ \displaystyle \tt \frac{z(4z^2-1)}{-(2z-1)}=0\\\\ \displaystyle \tt \frac{z(2z-1)(2z+1)}{-(2z-1)}=0\\\\ \displaystyle \tt z\cdot(-1)\cdot(2z+1)=0\\\\ \displaystyle \tt z(2z+1)=0\\\\ \displaystyle \tt \bold{z_1=0}\\\\ \displaystyle \tt 2z+1=0\\\\ \displaystyle \tt 2z=-1\\\\ \displaystyle \tt z=-1\div2\\\\ \displaystyle \tt \bold{z_2=-0,5}$