Question

Алгебра! 8 класс! лёгкое уровнение! срочно!!!!​

Answer 1

$\frac{2}{x-5}-\frac{4}{x+5}=\frac{x^{2}+15}{x^{2}-25}\\\\\frac{2}{x-5}-\frac{4}{x+5}-\frac{x^{2}+15}{(x-5)(x+5)}=0\\\\\frac{2(x+5)-4(x-5)-x^{2}-15 }{(x-5)(x+5)}=0\\\\\frac{2x+10-4x+20-x^{2}-15}{(x-5)(x+5)}=0\\\\\frac{-x^{2}-2x+15 }{(x-5)(x+5)}=0\\\\\left \{ {{x^{2}+2x-15=0 } \atop {x-5\neq0;x+5\neq0}} \right.\\\\\left \{ {{\left[\begin{array}{ccc}x_{1}=3 \\x_{2} =-5-neyd\end{array}\right } \atop {x\neq-5;x\neq5}} \right.\\\\Otvet:\boxed{3}$