Question

решите уравнения: sin(x3+п3)=-1

Answer 1

$sin(3x+3\pi )=-1\\3x+3\pi =\frac{3\pi }{2} +2\pi n$ , $n$ ∈ Ζ

$3x=-\frac{3\pi }{2} +2\pi n$ , $n$ ∈ Ζ

$x = -\frac{\pi }{2} +\frac{2\pi n }{3}$ , $n$ ∈ Ζ