Question

Найдите корни уравнения (2x+1)(x-4)=(x-2)(x+2)

Answer 1

Ответ:

$(2x + 1)(x - 4) = (x - 2)(x + 2) \\ 2 {x}^{2} - 8x + x - 4 = {x}^{2} - 4 \\ 2 {x}^{2} - 7x - 4 = {x}^{2} - 4 \\ 2 {x}^{2} - {x}^{2} - 7x - 4 + 4 = 0 \\ {x}^{2} - 7x = 0 \\ x(x - 7) = 0 \\ x = 0 \\ \\ x - 7 = 0 \\ x = 7$

Ответ: x=0; x=7