Question

Помогите пожалуйста решить задачи по физике

Answer 1

Ответ:

Объяснение:

#1

$n = \dfrac{c}{v} = \dfrac{3*10^8}{2.5*10^8} = 1.2$

#2

$n = \dfrac{\sin\alpha}{\sin\beta} = \dfrac{\sin60^\circ}{\sin30^\circ} = \sqrt{3}$

#3

$n = \dfrac{\sin\alpha}{\sin\beta} \to \sin\beta = \dfrac{\sin\alpha}{n} = \dfrac{\sin60^\circ}{2.5} = \dfrac{\sqrt{3}}{5} \to \beta \approx 20.27^\circ$

#4

$n = \dfrac{c}{v}\\n = \dfrac{\sin\alpha}{\sin\beta} \to \sin\beta = \dfrac{\sin\alpha}{n} = \dfrac{v*\sin\alpha}{c} = \dfrac{1.5*10^8*\sin45^\circ}{3*10^8} = \dfrac{\sqrt{2}}{4} \to \beta \approx 20.72^\circ$