Question

помогите срочно пжжж

Answer 1

1.

1) = 3(a - b)(a + b)

2) = 6(x - 2)(x + 2)

3) = x(x - 3)(x + 3)

4) = (b - 5)(b + 5)(b² + 25)

5) = -3(x-5)²

6) = 7y(3y - 2z)²

7) = (a + 1)(a - 3)(a + 3)

8) = (a + b - c)(a + b + c)

2.

1) => x³(x - 4)(x + 4) = 0

x₁³ = 0

x₁ = 0

x₂ - 4 = 0

x₂ = 4

x₃ + 4 = 0

x₃ = -4

2) => x(x + 3)² = 0

x₁ = 0

(x₂ + 3)² = 0

x₂ = -3

3) => (x - 6)(x - 1)(x + 1) = 0

x₁ - 6 = 0

x₁ = 6

x₂ - 1 = 0

x₂ = 1

x₃ + 1 = 0

x₃ = -1

3.

= (a² - 2b²)(a² + 2b²) = (a - b√2)(a + b√2)(a² + 2b²)