Question

Помогите решить пожалуйста

Answer 1

По теореме Виета:

х₁+х₂=-р

х₁х₂=q

$x_{1}+x_{2}=\frac{2}{3} +1\frac{1}{2}=\frac{13}{6} \\\\x_{1}\cdot x_{2}=\frac{2}{3} \cdot \frac{3}{2}=1\\\\-p=\frac{13}{6}\\\\p=-\frac{13}{6}; q=1 \\ \\x^2-\frac{13}{6}x+1=0\\\\6x^2-13x+6=0$

$x_{1}+x_{2}=\frac{3}{5} +(-1\frac{2}{3})=-\frac{16}{15} \\\\x_{1}\cdot x_{2}=\frac{3}{5} \cdot (-\frac{5}{3})=-1\\\\-p=-\frac{16}{15}\\\\p=\frac{16}{15}; q=-1 \\ \\x^2+\frac{16}{15}x-1=0\\\\15x^2+16x-15=0$