Question

решите примерыыыыыы пжжжжж​

Answer 1

  $\frac{3q^3-81p^3}{18p^2q+6q^2p+2q^3}+\frac{81q^2p-54qp^2+9p^3}{2qp^2-12pq^2+18q^3} =$

$=\frac{3(q^3-27p^3)}{2q(9p^2+3qp+q^2)}+\frac{9p(9q^2-6qp+p^2)}{2q(p^2-6pq+9q^2)} =$

$=\frac{3(q-3p)(9p^2+3pq+q^2)}{2q(9p^2+3qp+q^2)}+\frac{9p(9q^2-6qp+p^2)}{2q(9q^2-6pq+p^2)} =$

$=\frac{3(q-3p)}{2q}+\frac{9p}{2q} =$

$=\frac{3q-9p}{2q}+\frac{9p}{2q} =\frac{3q-9p+9p}{2q}=\frac{3q}{2q}=\frac{3}{2}=1,5$