Question

Решите пожалуйста интеграл

Answer 1

$\displaystyle\int\limits^0_{-3}\frac{3dx}{\sqrt{25+5x}}=\frac{3}{\sqrt{5}}\int\limits^0_{-3}\frac{d(5+x)}{\sqrt{5+x}}=\frac{6}{\sqrt5}\sqrt{5+x}|^0_{-3}=\\=\frac{6}{\sqrt5}(\sqrt5-\sqrt2)=6-6\sqrt\frac{2}{5}$