Question

(2+3а)+(а-2)=

-(-2а-4)-(3+5а)=

а+(а-10)-(12+а)=

Answer 1

Ответ:

1)(2+3а)+(а-2)=3a+a= 4а

2)-(-2а-4)-(3+5а)= 2a+4-3-5a= -3а+1

3)а+(а-10)-(12+а)=a+a-10-12-a= а-22