Question

4+2x-x2 и все в корне =x+2 помогите пожалуйста​

Answer 1

$\displaystyle \tt \sqrt{4 + 2x - {x}^{2} } = x + 2 \\ \displaystyle \tt 4 + 2x - {x}^{2} = {x}^{2} + 4x + 4 \\ \displaystyle \tt 2x - {x}^{2} = {x}^{2} + 4x \\ \displaystyle \tt 2x - 4x - {x}^{2} - {x}^{2} = 0 \\ \displaystyle \tt - 2x - 2 {x}^{2} = 0 \\ \displaystyle \tt - 2x(1 + x) = 0 \\ \displaystyle \tt x(1 + x) = 0 \\ \\ \displaystyle \tt \bold{x_1 = 0} \\ \\ \displaystyle \tt 1 + x = 0 \\ \displaystyle \tt \bold{x_2 = - 1}$