Question

решите няроунасть срочно 2х-1<9 ​

Answer 1

$\displaystyle \tt 2x-1<9\\\displaystyle \tt 2x<9+1\\\displaystyle \tt 2x<10\\\displaystyle \tt x<10\div2\\\displaystyle \tt x<5$

Ответ: $\displaystyle \tt x\in(-\infty; \: 5)$