Предмет: Физика, автор: Мика03

Задание что и в прошлом Картикам виднее, можете этот решить, но коротко просто формула и подставить , не надо пояснять! 50 баллов!

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Ответы

Автор ответа: Regent1828
1

1). Цена деления манометра: 0,2 МПа  (2 МПа на 10 делений)

2). Давление масла по манометру:  4,4 МПа

3). В гидравлическом прессе:

           F₁/S₁ = F₂/S₂  или так:   F₂/F₁ = S₂/S₁

    Так как давление масла одинаковое во всех точках, то:

           F₂ = pS₂ = 4,4·10⁶ · 65·10⁻⁴ = 28600 (H)

4). Сила, действующая на малый поршень:

           F₁ = pS₁ = 4,4·10⁶ · 2,5·10⁻⁴ = 1100 (H)

5). Выигрыш в силе:

           F₂/F₁ = 28600 : 1100 = 26 (раз)

    или так:

           S₂/S₁ = 65·10⁻⁴ : 2,5·10⁻⁴ = 26 (раз)


Мика03: Огромное спасибо!
Мика03: Огроменные спасибо!
Regent1828: Да не за что...)) Обращайтесь..)) Извините, что долго..))
Мика03: Здравствуйте, я задала новый вопрос, если не тяжело помогите решить! Заранее спасибо)
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