Question

${x}^{2} - 10x + 4 = 0$
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Answer 1

Ответ:

5+$\sqrt{21}$;  5-$\sqrt{21}$

Объяснение:

D= b^2-4ac = 100 - 16 = 84

$\sqrt{D}= \sqrt{84}$ = $2\sqrt{21}$

x1 = (-b+$\sqrt{D}$)/2a = (10+2$\sqrt{21}$)/2 = 5+$\sqrt{21}$

x2 = (-b-$\sqrt{D}$)/2a = (10-2$\sqrt{21}$)/2 = 5-$\sqrt{21}$