Question

(х-3)(2х-1)>(2х+1)(х+2)​ решите

Answer 1

$(x - 3)(2x - 1) > (2x + 1)(x + 2) = {2x}^{2} - x - 6x + 3 > {2x}^{2} + 4x + x + 2 = - x - 6x + 3 > 4x + x + 2 = - 7 + 3 > 5x + 2 = - 7 - 5x > 2 - 3 = - 12x > - 1 = x < \frac{1}{12}$