Question

Найдите квадрат суммы:
64+2*8*3p+9p^2=( )^2​

Answer 1

Ответ: 64+2*8*3p+9p^2 = (8+3p)^2

Answer 2

$\displaystyle \tt 64+2\cdot8\cdot3p+9p^2=8^2+2\cdot8\cdot3p+(3p)^2=\bold{(8+3p)^2}$