Question

розв'яжіть прошу)$x^{2} =5;\\\sqrt{x}=9;\\x^{2} =-4;\\(x^{2}-9)*\sqrt{x-2}=0$

Answer 1

$x^{2} =5; \: \: x = \sqrt{5} \\ \sqrt{x}=9; \: x = 3\\x^{2} =-4; \: x = не \: сущ\\(x^{2}-9)*\sqrt{x-2}=0 \: \\ x = - 3 \: \: x = 3 \: \: x = 2$