Question

Решите уравнение 3х/х+5 +1=10/х2+10х+25

Answer 1

одз х≠5

$\frac{3}{x+5} +1-\frac{10}{x^{2}+10x+25 }=0\\\\ \frac{3}{x+5} +1-\frac{10}{(x+5)^{2} } =0\\\\\frac{3(x+5)+(x+5)^{2}-10 }{(x+5)^{2} } =0\\\\\frac{13x+30+x^{2} }{(x+5)^{2} } =0\\\\13x+30+x^{2} =0\\\\x^{2}+10x+3x+30=0\\x(x+10)*3(x+10)=0 \\(x+10)*(x+3)=0$

$x+10=0\\x+3=0\\x=-10\\x=-3$