Question

найдите нули Функции
$- 3 {x}^{2} - 3x + 1$
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Answer 1

$y= - 3 {x}^{2} - 3x + 1$

$- 3 {x}^{2} - 3x + 1=0$

$3 {x}^{2} + 3x - 1=0$

$D= 3^2-4\cdot3\cdot(-1)=9+12=21$

$x=\dfrac{-3\pm\sqrt{21} }{2\cdot3} =\dfrac{-3\pm\sqrt{21} }{6}$

Ответ: $x=\dfrac{-3\pm\sqrt{21} }{6}$