Question

Сократите дробь:
$\frac{12-5-2x^2}{15-10x}$

Answer 1

$\displaystyle \tt \frac{12-5-2x^2}{15-10x}=\frac{-2x^2-5x+12}{-10x+15}=\frac{-2x^2+3x-8x+12}{-5(2x-3)}=\\\\\\ \displaystyle \tt =\frac{-x(2x-3)-4(2x-3)}{-5(2x-3)}=\frac{-(2x-3)(x+4)}{-5(2x-3)}=\frac{-(x+4)}{-5}=\\\\\\ \displaystyle \tt =\bold{\frac{x+4}{5}}$