Question

Помогите сделать 14 номер​

Answer 1

Объяснение:

$\begin{array}{l}\mathrm{5CH_{3}-CH_{2}-\overset{+1}{C}HO + 2K\overset{+7}{Mn}O_{4} + 3H_{2}SO_{4} =} \\ \mathrm{= 5CH_{3}-CH_{2}-\overset{+3}{C}OOH + 2\overset{+2}{Mn}SO_{4} + K_{2}SO_{4} + 3H_{2}O}\end{array} \\\\\\\left.\begin{array}{r}\mathrm{C^{+1} -2e^{-} \to C^{+3}} \\\mathrm{Mn^{+7} +5e^{-} \to Mn^{+2}}\end{array}\right|10\left|\begin{array}{l}\mathrm{5 - reducing\;agent} \\\mathrm{2 - oxidizing\;agent}\end{array}\right.$

P.S. reducing agent - восстановитель

oxidizing agent - окислитель