Question

решите уравнение
x(x+3)=5

Answer 1

в закрепе,дискриминант не писала

Answer 2

$\displaystyle \tt x(x+3)=5\\\displaystyle \tt x\cdot x+x\cdot3=5\\\displaystyle \tt x^2+3x=5\\\displaystyle \tt x^2+3x-5=0\\\displaystyle \tt D=3^2-4\cdot1\cdot(-5)=9+20=29\\\\ \displaystyle \tt \bold{x_1}=\frac{-3+\sqrt{29}}{2}\\\\ \displaystyle \tt \bold{x_2}=\frac{-3-\sqrt{29}}{2}$