Question

решите уравнение
(x-2)(x+3)=-2

Answer 1

$\displaystyle \tt (x-2)(x+3)=-2\\\displaystyle \tt x^2+3x-2x-6=-2\\\displaystyle \tt x^2+x-6-2=0\\\displaystyle \tt x^2+x-4=0\\\displaystyle \tt D=1^2-4\cdot1\cdot(-4)=1+16=17\\\displaystyle \tt \sqrt{D}=\sqrt{17}\\\\ \displaystyle \tt \bold{x_1}=\frac{-1+\sqrt{17}}{2}\\\\ \displaystyle \tt \bold{x_2}=\frac{-1-\sqrt{17}}{2}$