Question

(5-3y)-(4-2y)=y-8-(y-1)

Answer 1

Решение:

5-3у-4+2у=у-8-у+1

1-у= - 7

-у= - 7-1

-у= - 8

Ответ:

У=8

Answer 2

$\displaystyle \tt (5-3y)-(4-2y)=y-8-(y-1)\\\displaystyle \tt 5-3y-4+2y=y-8-y+1\\\displaystyle \tt 1-y=-7\\\displaystyle \tt -y=-7-1\\\displaystyle \tt -y=-8\\\displaystyle \tt \bold{y=8}$