Question

5cos(3x-2)-4=0 решение​

Answer 1

$5 \cos(3x - 2) - 4 = 0 \\ \cos(3x - 2) = \frac{4}{5} \\ 3x - 2 = ± \arccos \frac{4}{5} + 2\pi n \\ 3x = ± \arccos\frac{4}{5}+ 2 + 2\pi n \\ x = ±\frac{1}{3} \arccos \frac{4}{5} + \frac{2}{3} + \frac{2\pi}{3} n, \: n \in Z$