Question

Срочно 30 баллов
задание в приложении

Answer 1

$\displaystyle \tt \left \{ {{\displaystyle \tt \frac{x}{y}+\frac{y}{x}=2\frac{1}{2}} \atop {\displaystyle \tt 2x-3y=3}} \right. \: \to \: \left \{ {{\displaystyle \tt \frac{x}{y}+\frac{y}{x}=\frac{5}{2}} \atop {\displaystyle \tt x=\frac{3}{2}+\frac{3}{2}y}} \right. \\\\\\ \displaystyle \tt \frac{\frac{3}{2}+\frac{3}{2}y}{y}+\frac{y}{\frac{3}{2}+\frac{3}{2}y}=\frac{5}{2}\\\\\displaystyle \tt \bold{y=-\frac{3}{2}\:,\:\: y_2=3}$

$\displaystyle \tt \left \{ {{\displaystyle \tt x=\frac{3}{2}+\frac{3}{2}\cdot\bigg(-\frac{3}{2}\bigg)} \atop {\displaystyle \tt x=\frac{3}{2}+\frac{3}{2}\cdot3}} \right. \: \to \: \left \{ {{\bold{x=-\frac{3}{4}}} \atop {\displaystyle \tt \bold{x_2=6}}} \right.$

ОТВЕТ:

$\displaystyle \tt (x_1; \: y_1)=\bigg(-\frac{3}{4}; \: -\frac{3}{2}\bigg)\\\\ \displaystyle \tt (x_2; \: y_2)=(6; \: 3)$