Question

Сократи дробь (x2-25)/(x2 +3x-40)​

Answer 1

$\displaystyle \tt \frac{x^2-25}{x^2+3x-40}=\frac{(x-5)(x+5)}{x^2+8x-5x-40}=\frac{(x-5)(x+5)}{x(x+8)-5(x+8)}=\frac{(x-5)(x+5)}{(x+8)(x-5)}=\\\\\\\displaystyle \tt =\bold{\frac{x+5}{x+8}}$