Question

Решите уравнение 2/3|5x-4|+8,6=10

Answer 1

$\displaystyle \tt \frac{2}{3}\cdot|5x-4|+8,6=10\\\\ \displaystyle \tt \frac{2}{3}\cdot|5x-4|+\frac{43}{5}=10\:\:\:\:\:\bigg|\cdot15\\\\ \displaystyle \tt 10\cdot|5x-4|+129=150\\\displaystyle \tt 10\cdot|5x-4|=150-129\\ \displaystyle \tt 10\cdot|5x-4|=21\\\displaystyle \tt |5x-4|=21\div10\\ \displaystyle \tt |5x-4|=2,1\\\\ \displaystyle \tt 5x-4=2,1\\\displaystyle \tt 5x=2,1+4\\\displaystyle \tt 5x=6,1\\\displaystyle \tt x=6,1\div5\\\displaystyle \tt \bold{x_1=1,22}$

$\displaystyle \tt 5x-4=-2,1\\\displaystyle \tt 5x=-2,1+4\\\displaystyle \tt 5x=1,9\\\displaystyle \tt x=1,9\div5\\\displaystyle \tt \bold{x_2=0,38}$