Question

ЗАПОЛНИТЕ ТАБЛИЦУ!!ОЧЕЕЬ СРОЧНО!НАПИСАТЬ ВСЁ С ОБЬЯСНЕНИЕМ!ДАЮ 48 БАЛЛОВ!!​

Answer 1

Решение во вложении:

Answer 2

Ответ:

Таблица во вложении

Объяснение:

$1) a+\frac{4}{a} = -2 + \frac{4}{-2} = -2 - 2 = -4\\\\a+\frac{4}{a} = -1 + \frac{4}{-1} = -1 - 4 = -5\\\\a+\frac{4}{a} = 0 + \frac{4}{0} = \varnothing\\\\a+\frac{4}{a} = 1 + \frac{4}{1} = 1 + 4 = 5\\\\a+\frac{4}{a} = 2 + \frac{4}{2} = 2 + 2 = 4$

$2) \frac{5}{a^2-1} = \frac{5}{(-2)^2-1} = \frac{5}{4-1} = \frac{5}{3} = 1\frac{2}{3}\\\\\frac{5}{a^2-1} = \frac{5}{(-1)^2-1} = \frac{5}{1-1} = \frac{5}{0} = \varnothing\\\\\frac{5}{a^2-1} = \frac{5}{0^2-1} = \frac{5}{0-1} = \frac{5}{-1} = -5\\\\\frac{5}{a^2-1} = \frac{5}{1^2-1} = \frac{5}{1-1} = \frac{5}{0} = \varnothing\\\\\frac{5}{a^2-1} = \frac{5}{2^2-1} = \frac{5}{4-1} = \frac{5}{3} = 1\frac{2}{3}$

$3)\frac{a-1}{a^2+1} = \frac{(-2)-1}{(-2^2)+1} = \frac{-3}{4+1} = -\frac{3}{5}\\\\\frac{a-1}{a^2+1} = \frac{(-1)-1}{(-1^2)+1} = \frac{-2}{1+1} = -\frac{2}{2} = -1\\\\\frac{a-1}{a^2+1} = \frac{1-1}{(1^2)+1} = \frac{0}{1+1} = \frac{0}{2} = 0\\\\\frac{a-1}{a^2+1} = \frac{2-1}{(2^2)+1} = \frac{1}{4+1} = \frac{1}{5}$