Question

Решите неравенство..​

Answer 1

Ответ:

$-\sqrt3-2sinx>0\\\\2sinx<-\sqrt3\\\\sinx<-\frac{\sqrt3}{2}\\\\-\frac{2\pi}{3}+2\pi n<x<-\frac{\pi}{3}+2\pi n\; ,\; n\in Z\\\\x\in (-\frac{2\pi}{3}+2\pi n\; ;\; -\frac{\pi}{3}+2\pi n)\; ,\; n\in Z$