Предмет: Физика, автор: nikitagudkovskij50

Какое количество теплоты выделится в проводнике с электрическим сопротивлением 10 Ом за 5 секунд при силе тока в цепи 4 А

Ответы

Автор ответа: nikkimikki200310
2
Q = UIt
U = IR = 4 * 10 = 40 В
Q = 40 * 4 * 5 = 800 Дж
Автор ответа: serovaksusa1
2

Ответ:

Дано I=4A

R=10Oм

t=5сек

Найти Q

A=Q=I^2 *R*t

Q=4^2 *10*5=800Дж

Ответ Q=800Дж

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