Question

ПОЖАЛУЙСТА Прошууу!!!!! ПОМОГИТЕ
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Answer 1

Решение во вложении:

Answer 2

$1)\; \; 2x^4-32=2(x^4-16)=2(x^2-4)9x^2+4)=2(x-2)(x+2)(x^2+4)\\\\\\2)\; \; S=6a^2=6(4x-5)^2\\\\V=a^3=(4x-5)^3$

$3)\; \; 87^2-174\cdot 67+67^2=87^2-2\cdot 87\cdot 67+67^2=(87-67)^2=20^2=400\\\\\frac{38^2-17^2}{47^2-361}=\frac{(38-17)(38+17)}{(47-19)(47+19)}=\frac{21\cdot 55}{28\cdot 66}=\frac{3\, \cdot \, 5}{4\, \cdot \, 6}=\frac{5}{8}$

$4)\; \; \left \{ {{x-y=34} \atop {x^2-y^2=408}} \right.\; \; \left \{ {{x-y=34\qquad \; \; \; } \atop {(x-y)(x+y)=408}} \right.\; \; \left \{ {{x-y=34\; \; \; } \atop {34(x+y)=408}} \right.\; \; \left \{ {{x-y=34} \atop {x+y=12}} \right.\\\\\left \{ {{2x=46\; \; } \atop {2y=-22}} \right.\; \; \left \{ {{x=23\; \; } \atop {y=-11}} \right.\\\\Otvet:\; \; x=23\; \; ,\; \; y=-11\; .$