Question

x^2+5x-4=0 pleaseee​

Answer 1

x²+5x-4=0

Ищем по дискриминанту:

D = b² - 4*a*c

D = 5² - 4 *1 * (-4) = 25 + 16 = 41

$x1.2 = \frac{ - b + - \sqrt{D} }{2a}$

[tex]x1 = \frac{-5 + \sqrt{41} }{2}

[tex]x2 = \frac{-5 - \sqrt{41} }{2}

Answer 2

Ответ:

Пошаговое объяснение:

$\[\begin{gathered}{x^2}+5x-4=0 \hfill \\D={b^2}-4ac={5^2}-4\cdot 1\cdot (-4)=25+16=41 \hfill \\{x_{1;2}}=\frac{{-b\pm \sqrt D }}{{2a}}=\frac{{-5\pm \sqrt {41}}}{{2\cdot 1}} = \frac{{-5\pm\sqrt {41} }}{2} \hfill \\{x_1}=\frac{{-5+\sqrt {41} }}{2} \hfill \\{x_2}=\frac{{-5-\sqrt {41} }}{2} \hfill \\ \end{gathered} \]$