Question

Помогите СОЧ УМОЛЯЮ
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Answer 1

Ответ:

$( {x}^{2} - {(x - 1)}^{2} ) + ( {(x - 2)}^{2} - {(x - 3)}^{2} ) = 30 \\ {x}^{2} - {x}^{2} + 2x - 1 + {x}^{2} - 4x + 4 - {x}^{2} + 6x - 9 = 30 \\ 4x - 6 = 30 \\ 4x = 36 \\ x = 9$

Первое число 9

Второе 8

Треье 7

Четверное 6

Проверим

$( {9}^{2} - {8}^{2} ) + ( {7}^{2} - {6}^{2} ) = (81 - 64) + (49 - 36) = 17 + 13 = 30$