Question

Логарифмическое неравенство 3

Answer 1

$log_{\frac{1}{2} }log_{3}(1-x)>log_{\frac{1}{2} }2$

$\left \{ {log_{3}(1-x)>0} \atop {log_{3}(1-x)<2}} \right. \left \{{1-x>0} \atop { {log_{3}(1-x)>log_{3}1} \atop {log_{3}(1-x)<log_{3}9}} \right. \left \{ {{1-x>1} \atop {1-x<9}} \right. \left \{ {{x<0} \atop {x>-8}} \right.$

О т в е т. (-8;0)