Question

Пж решите,даю 15 баллов !!!!!!!!​

Answer 1

Решение во вложении:

Answer 2

$\displaystyle \tt 1). \ (a-b)^{3}-3(a-b)^{2}=(a-b)^{2}(a-b-3);\\\\2). \ (x+y)^{3}+2x(x+y)^{2}=(x+y)^{2}(x+y+2x)=(x+y)^{2}(3x+y);\\\\3). \ (m+n)^{3}-m^{2}-2mn-n^{2}=(m+n)^{3}-(m+n)^{2}=(m+n)^{2}(m+n-1);\\\\4). \ x^{2}-4xy+4y^{2}-(x-2y)^{3}=(x-2y)^{2}-(x-2y)^{3}=\\\\{} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =(x-2y)^{2}(1-x+2y);$