Question

Значение выражения $\frac{5}{12} lk +(-\frac{1}{6} lk)+lk+(4lk-14lk)$ равно...
1) 4lk
2) 5lk
3) $3\frac{1}{4}$lk
4) $4\frac{6}{12}$lk

Answer 1

$\frac{5}{12} lk +(-\frac{1}{6} lk)+lk+(4lk-14lk) =\frac{5}{12} lk -\frac{2}{12} lk+lk-10lk=\\\\1\frac{3}{12} lk-10lk=1\frac{3}{12} lk-9\frac{12}{12}lk=-8\frac{9}{12}lk=-8\frac{3}{4}lk$