Question

2x^2+7x+3=0 plesssseee​

Answer 1

$2x^{2} +7x+3=0$

$D=b^{2} -4ac=49-24=25$

$x_{1} =-b+\sqrt{D} /2a=-7+5/4=-1/2$

$x_{2} =-b-\sqrt{D} /2a=-7-5/4=-3$

Ответ: -3; -1/2