Question

Брат помоги) Решите уравнение.​

Answer 1

$\displaystyle \tt (3x-2)^2+(1-3x)(3x+2)=36\\\displaystyle \tt 9x^2-12x+4+3x+2-9x^2-6x=36\\\displaystyle \tt -15x+6=36\\\displaystyle \tt -15x=36-6\\\displaystyle \tt -15x=30\\\displaystyle \tt x=30\div(-15)\\\displaystyle \tt \bold{x=-2}$