Question

Плиз сделать как можно быстрее очень надо ​

Answer 1

как - то так ..........................

Answer 2

Ответ:

▪︎1

a)

$1.5 {x}^{2} {y}^{2} \:$

б)

$\frac{x(x + 2)}{2} \:$

в)

$\frac{3a - 6}{a + 3} \:$

▪︎2.

$4$

Объяснение:

▪︎1.

a)

$\frac{9 {x}^{6} }{ {y}^{3} } \div \frac{6 {x}^{4} }{ {y}^{5} } = \frac{9 {x}^{6} \times {y}^{5} }{ {y}^{3} \times 6 {x}^{4} } = \frac{3 {x}^{2} {y}^{2} }{2} = 1.5 {x}^{2} {y}^{2}$

б)

$\frac{4 {x}^{3} }{x + 2} \times \frac{ {x}^{2} + 4x + 4}{8 {x}^{2} } = \frac{x(x + 2) ^{2} }{(x + 2) \times 2} = \frac{x(x + 2)}{2}$

в)

$\frac{3a - 9}{a + 2} \div \frac{ {a}^{2} - 9}{ {a}^{2} - 4} = \frac{3(a - 3)}{a + 2} \times \frac{ {a}^{2} - 4}{ {a}^{2} - 9} = \frac{3(a - 3)}{a + 2} \times \frac{(a - 2)(a + 2)}{(a - 3)(a + 3)} = \frac{3(a - 2)}{a + 3} = \frac{3a - 6}{a + 3}$

▪︎2.

$( \frac{x + y}{x - y} - \frac{x - y}{x + y} ) \div \frac{xy}{ {x}^{2} - {y}^{2} } = \frac{(x + y)(x - y)(x + y)}{(x - y)xy} - \frac{(x - y)(x - y)(x + y)}{(x + y)xy} = \frac{{(x + y)}^{2} }{xy} - \frac{ {(x - y)}^{2} }{xy} = \frac{(x + y - x + y))(x + y + x - y)}{xy} = \frac{2y \times 2x}{xy} = 4$