Question

$109 \frac{1}{5} \div (5 \frac{9}{25} + \frac{10.08 - 20.16x}{0.8})$
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Answer 1

Ответ:

$\frac{2730}{449 - 630x}$

вот таким должен быть ответ

Answer 2

$\displaystyle \tt 109\frac{1}{5}\div\bigg(5\frac{9}{25}+\frac{10,08-20,16x}{0,8}\bigg)=\frac{546}{5}\div\bigg(\frac{134}{25}+\frac{\frac{252}{25}-\frac{504}{25}x}{\frac{4}{5}}\bigg)=\\\\\displaystyle \tt =\frac{546}{5}\div\bigg(\frac{134}{25}+\frac{\frac{252-504x}{25}}{\frac{4}{5}}\bigg)=\frac{546}{5}\div\bigg(\frac{134}{25}+\frac{252-504x}{20}\bigg)=\\\\\displaystyle \tt =\frac{546}{5}\div\bigg(\frac{134}{25}+\frac{4(63-126x)}{20}\bigg)=\frac{546}{5}\div\bigg(\frac{134}{25}+\frac{63-126x}{5}\bigg)=$

$\displaystyle \tt \\=\frac{546}{5}\div\frac{134+5(63-126x)}{25}=\frac{546}{5}\div\frac{134+315-630x}{25}=\\\\ \displaystyle \tt =\frac{546}{5}\div\frac{449-630x}{25}=\frac{546}{5}\cdot\frac{25}{449-630x}=546\cdot\frac{5}{449-630x}=\\\\\displaystyle \tt =\bold{\frac{2730}{449-630x}}$