Question

Помогите с математикой

Answer 1

$a * b = |a| * |b| * cos(a) = a_1b_1+a_2b_2+a_3b_3 => cos(a) = \frac{a_1b_1+a_2b_2+a_3b_3}{ |a| * |b|}\\|a| = \sqrt{a_1^2 + a_2^2+a_3^2} = \sqrt{4 + 9 +9} = \sqrt{22}\\|b| = \sqrt{b_1^2+b_2^2+b_3^2} = \sqrt{36+16+64} = \sqrt{116} = 2\sqrt{29}\\cos(a) = \frac{-12 - 12 - 24}{2\sqrt{29}*\sqrt{22}} = -\frac{24}{\sqrt{638}} \neq 0 => a = arccos(-\frac{24}{\sqrt{638}}) \neq \frac{\pi }{2}$

Ответ: нет